Forum > How to get filename of uploaded file during POST

03-18-2023, 07:52 AM:

I am implementing a file upload function similar to the PostDataDemo (https://github.com/Atozed/IntraWeb/tree/...stDataDemo) and is working fine. However, I am wondering if there is a way to extract the filename in the ContentHandler? The aRequest.File object only contains the temporary filename (.tmp) and not the original filename.

03-21-2023, 06:39 AM:

Within the content handler you have various information about the file, not only the temporary file name.

Here is the code form that example:

Code:

function TContentXML.Execute(aRequest: THttpRequest; aReply: THttpReply; const aPathname: string; aSession: TIWApplication;

aParams: TStrings): boolean;

var

xFile: THttpFile;

xml: string;

begin

Result := False;

if aRequest.Files.Count = 1 then begin

xFile := THttpFile(aRequest.Files[0]);

xml := TIWTextFileReader.ReadAllText(xFile.TempPathName);

aReply.WriteString(ClassName + '.Execute - Content received: ' + xml);

Result := True;

end;

These are the properties that you can get from the "xFile" variable above:

property FileName: TFileName;

property TempPathName: TFileName;

property ContentType: string;

property FileSize: Int64;

property FieldName: string;

property FileSize_WebApi: Int64;

property LastModified_WebApi: TDateTime;

property MIMEType_WebApi: string;

The _WebApi suffixed properties may or may not be available (it depends on the browser).