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+----- Thread: How to get filename of uploaded file during POST (/thread-3072.html)
How to get filename of uploaded file during POST - dbrain23 - 03-18-2023
I am implementing a file upload function similar to the PostDataDemo (https://github.com/Atozed/IntraWeb/tree/master/15/Delphi/PostDataDemo) and is working fine. However, I am wondering if there is a way to extract the filename in the ContentHandler? The aRequest.File object only contains the temporary filename (.tmp) and not the original filename.
RE: How to get filename of uploaded file during POST - Alexandre Machado - 03-21-2023
Within the content handler you have various information about the file, not only the temporary file name.
Here is the code form that example:
Code:
function TContentXML.Execute(aRequest: THttpRequest; aReply: THttpReply; const aPathname: string; aSession: TIWApplication;
aParams: TStrings): boolean;
var
xFile: THttpFile;
xml: string;
begin
Result := False;
if aRequest.Files.Count = 1 then begin
xFile := THttpFile(aRequest.Files[0]);
xml := TIWTextFileReader.ReadAllText(xFile.TempPathName);
aReply.WriteString(ClassName + '.Execute - Content received: ' + xml);
Result := True;
end;
end;These are the properties that you can get from the "xFile" variable above:
property FileName: TFileName;
property TempPathName: TFileName;
property ContentType: string;
property FileSize: Int64;
property FieldName: string;
property FileSize_WebApi: Int64;
property LastModified_WebApi: TDateTime;
property MIMEType_WebApi: string;
The _WebApi suffixed properties may or may not be available (it depends on the browser).